3^4x=9^2+x

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Solution for 3^4x=9^2+x equation: 



3^4x=9^2+x

We move all terms to the left:

3^4x-(9^2+x)=0

We get rid of parentheses

3^4x-x-9^2=0

We add all the numbers together, and all the variables

-1x+3^4x-81=0

We move all terms containing x to the left, all other terms to the right

-1x+3^4x=81

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